Calculate the greatest (highest) common factor (divisor)
gcf, hcf, gcd (21,212,235; 12,121,314) = ?
Method 1. The prime factorization:
The prime factorization of a number: finding the prime numbers that multiply together to make that number.
21,212,235 = 32 × 5 × 11 × 42,853
21,212,235 is not a prime number but a composite one.
12,121,314 = 2 × 3 × 59 × 97 × 353
12,121,314 is not a prime number but a composite one.
- Prime number: a natural number that is only divisible by 1 and itself. A prime number has exactly two factors: 1 and itself.
- Composite number: a natural number that has at least one other factor than 1 and itself.
Calculate the greatest (highest) common factor (divisor):
Multiply all the common prime factors, taken by their smallest exponents (the smallest powers).
Step 1. Divide the larger number by the smaller one:
21,212,235 ÷ 12,121,314 = 1 + 9,090,921
Step 2. Divide the smaller number by the above operation's remainder:
12,121,314 ÷ 9,090,921 = 1 + 3,030,393
Step 3. Divide the remainder of the step 1 by the remainder of the step 2:
9,090,921 ÷ 3,030,393 = 2 + 3,030,135
Step 4. Divide the remainder of the step 2 by the remainder of the step 3:
3,030,393 ÷ 3,030,135 = 1 + 258
Step 5. Divide the remainder of the step 3 by the remainder of the step 4:
3,030,135 ÷ 258 = 11,744 + 183
Step 6. Divide the remainder of the step 4 by the remainder of the step 5:
258 ÷ 183 = 1 + 75
Step 7. Divide the remainder of the step 5 by the remainder of the step 6:
183 ÷ 75 = 2 + 33
Step 8. Divide the remainder of the step 6 by the remainder of the step 7:
75 ÷ 33 = 2 + 9
Step 9. Divide the remainder of the step 7 by the remainder of the step 8:
33 ÷ 9 = 3 + 6
Step 10. Divide the remainder of the step 8 by the remainder of the step 9:
9 ÷ 6 = 1 + 3
Step 11. Divide the remainder of the step 9 by the remainder of the step 10:
6 ÷ 3 = 2 + 0
At this step, the remainder is zero, so we stop:
3 is the number we were looking for - the last non-zero remainder.
This is the greatest (highest) common factor (divisor).
The greatest (highest) common factor (divisor):
gcf, hcf, gcd (21,212,235; 12,121,314) = 3
The two numbers have common prime factors